45x^2+3x-6=0

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Solution for 45x^2+3x-6=0 equation:



45x^2+3x-6=0
a = 45; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·45·(-6)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*45}=\frac{-36}{90} =-2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*45}=\frac{30}{90} =1/3 $

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